Mathematics is a typical subject where you just juggle with equations, always in search of funny logic to balance it. Those who love this subject, just find themselves in a sea of never-ending mystery. Puzzle Duniya always thinking about those typical math-fans and thus brings a bunch of logical escalations for them.

Below, you will find out few mathematical riddles with their logical explanation and audio-visual analysis. Just go through them and enjoy the session. If you are really curious to juggle around this subject matter, then you must find your time to spend here to learn something interesting.

So, just come, read and enjoy it……

**Exercise 1:**

2 * 2 = 44

4 * 4 = 168

6 * 6 = 3612

Then 9 * 9 = ?????

**Solution:**

Let’s denote every row in the above equation as i), ii), iii) and iv).

From the 1st row of equation, we get 2 * 2 = 44

If we multiply 2 with 2, we get 2 * 2 = 4, then adding 2 with itself, we get 2 + 2 = 4

Now the final equation stands here is: (2 * 2) | (2 + 2) = 4 | 4 = 44, where ‘|’ indicates the two digits kept together.

Similarly From the 2nd row of equation, we get 4 * 4 = 16

If we multiply 4 with 4, we get 4 * 4 = 16, then adding 4 with itself, we get 4 + 4 = 8

Now the final equation stands here is: (4 * 4) | (4 + 4) = 16 | 8 = 168, where ‘|’ indicates the two digits kept together.

From the 3rd row of equation, we get 6 * 6 = 36

If we multiply 6 with 6, we get 6 * 6 = 36, then adding 6 with itself, we get 6 + 6 = 12

Now the final equation stands here is: (6 * 6) | (6 + 6) = 36 | 12 = 3612, where ‘|’ indicates the two digits kept together.

Finally from the 4th row of equation, we get 9 * 9 = 81

If we multiply 9 with 9, we get 9 * 9 = 81, then adding 9 with itself, we get 9 + 9 = 18

Now the final equation stands here is: (9 * 9) | (9 + 9) = 18 | 18 = 8118 ((?????), where ‘|’ indicates the two digits kept together.

So the ‘?’ will be replaced with 8118

**Exercise 2:**

1 + 4 = 5

2 + 5 = 12

3 + 6 = 21

8 + 11 = ?????

**Solution:**

Let’s denote every row in the above equation as i), ii), and iii)

From the 1st row of equation, 1 + 4 = 5

Let’s denote every digit from L.H.S to R.H.S as a, b and c

So, here from the 1st row of equation, we get a = 1, b = 4 and c = 5

Now from L.H.S, we get (a * b) + a = (1 * 4) + 1 = 5 = c

So, (a * b) + a = c

Putting the same logic in every row of equation, we get:

(2 * 5) + 2 = 10 + 2 = 12

(3 * 6) + 3 = 18 + 3 = 21

and (8 * 11) + 8 = 88 + 8 = 96 (?????)

**Exercise 3:**

Book + Book + Book = Clock + (Pen + Pen)

Clock = Pen + Pen + Pen + Pen

Pen + Pen + Pen = 15

Book = ????

**Solution:**

Let’s denote every row in the above equation as i), ii), and iii)

From the 1st row of equation, we get Book + Book + Book = Clock + (Pen + Pen)

∴ 3 Books = Clock + 2Pens

From the 3rd row of equation, we get Pen + Pen + Pen = 15

∴ 3 Pens = 15

∴ 1 Pen = 15/3 = 5

Now, putting the value of 1 Pen in the 1st row of equation, we get:

3 Books = Clock + (2 * 5) = Clock + 10

From 2nd row of equation, we get Clock = 4 pens = 4 * 5 = 20

So, 3 Books = 20 + 10 = 30

∴ 1 Book = 30/3 = 10

So, the value of 1 Book will be 10 (????)

**Exercise 4:**

16 ÷ 4 = 74

21 ÷ 7 = 37

81 ÷ 9 = 99

55÷ 5 = ????

**Solution:**

Let’s denote every row in the above equation as i), ii), iii) and iv).

From the 1st row of equation, we get 16 ÷ 4 = 74

Let’s denote every digit from L.H.S as a, b and c

So, here from the 1st row of equation, we get a = 1, b = 6 and c = 4

Now from L.H.S, we get (a + b) | c = (1 + 6) | 4 = 7 | 4 = 74, where ‘|’ indicates the two digits kept together.

So, (a + b) |c = R.H.S

Similarly, from the 2nd row of equation, we get 21 ÷ 7 = 37

Let’s denote every digit from L.H.S as a, b and c

So, here from the 2nd row of equation, we get a = 2, b = 1 and c = 7

Now from L.H.S, we get (a + b) | c = (2 + 1) | 7 = 3 | 7 = 37, where ‘|’ indicates the two digits kept together.

So, (a + b) |c = R.H.S

Similarly, from the 3rd row of equation, we get 81 ÷ 9 = 99

Let’s denote every digit from L.H.S as a, b and c

So, here from the 2nd row of equation, we get a = 2, b = 1 and c = 7

Now from L.H.S, we get (a + b) | c = (8 + 1) | 9 = 9 | 9 = 37, where ‘|’ indicates the two digits kept together.

So, (a + b) |c = R.H.S

Finally, from the 4th row of equation, we get: 55÷ 5

Putting the same logic as above, we get the actual value,

(a + b) | c = (5 + 5) | 5 = 10 | 5 = 105